Guides
Chem/Phys5D: Structure, function, and reactivity of biologically relevant molecules

Acid Derivatives (Anhydrides, Amides, Esters)

Acid derivatives are among the most biologically important functional groups on the MCAT: every peptide bond is an amide, every fat and phospholipid contains ester linkages, and one mechanism — nucleophilic acyl substitution — governs all of their reactivity. Master that pattern and you can predict reactivity, drive interconversions, and understand how enzymes manipulate these bonds.

Priority labels: Must know = cold; Know the logic = mechanism not names; Passage-level = recognize, don't memorize; Optional = skippable.


Structure and Nomenclature

The Carbonyl Group Is the Unifying Feature

Must know

All acid derivatives share a carbonyl (C=O\ce{C=O}) bearing a leaving group. That leaving group controls both reactivity and name. When a nucleophile attacks the carbonyl carbon, the leaving group departs — this is why these compounds undergo substitution, while aldehydes and ketones (no leaving group) undergo addition.

The parent is the carboxylic acid (RCOOH\ce{RCOOH}); replace OH\ce{-OH} to get the derivatives:

DerivativeStructureLeaving Group
Acid chlorideRCOCl\ce{RCOCl}ClX\ce{Cl^-}
Acid anhydrideRCOOCORX\ce{RCOOCOR'}RCOOX\ce{RCOO^-} (carboxylate)
EsterRCOORX\ce{RCOOR'}RXOX\ce{R'O^-} (alkoxide)
AmideRCONHRX\ce{RCONHR'}amine (or NHX4X+\ce{NH4+} under acid)
ThioesterRCOSRX\ce{RCOSR'}RXSX\ce{R'S^-} (thiolate)

Acid chlorides are most reactive; esters, amides, and anhydrides dominate biological passages; thioesters (acetyl-CoA) appear in metabolism.

Nomenclature Rules

Must know
  • Esters: alkyl alkanoate — alkyl from the alcohol, alkanoate from the acid. Ethyl acetate = CHX3COOCX2HX5\ce{CH3COOC2H5}. Always identify which carbon bears the carbonyl ("acid" part).
  • Amides: swap "-oic acid" for "-amide"; N-substituents get an "N-" prefix (N-methylacetamide = CHX3CONHCHX3\ce{CH3CONHCH3}).
  • Anhydrides: replace "acid" with "anhydride" (acetic anhydride = (CHX3CO)X2O\ce{(CH3CO)2O}).

β-Lactam: a cyclic amide with N and the carbonyl carbon in a four-membered ring; "β" = nitrogen on the carbon β to the carbonyl. Found in penicillins/cephalosporins.

Quick check: What is the IUPAC name of CHX3CHX2COOCHX3\ce{CH3CH2COOCH3}?

Answer: Methyl propanoate. "Methyl" from the alcohol (OCHX3\ce{-OCH3}), "propanoate" from propanoic acid (CHX3CHX2COOH\ce{CH3CH2COOH}).


Physical Properties

Boiling Points and Solubility

Must know

Physical properties come down to intermolecular forces. Amides both donate (N–H) and accept (C=O\ce{C=O}) hydrogen bonds, so they boil unusually high. Esters and anhydrides are H-bond acceptors only (dipole-dipole, no donor) → lower bp than the parent acid but above comparable alkanes. Approximate trend at similar MW:

Amide>Carboxylic acid>Anhydride>EsterAcid chloride>Alkane\text{Amide} > \text{Carboxylic acid} > \text{Anhydride} > \text{Ester} \approx \text{Acid chloride} > \text{Alkane}

Solubility: short-chain esters/amides are water-soluble (carbonyl O accepts H-bonds); long chains are hydrophobic — short fatty-acid esters dissolve, triglycerides don't.

Amide resonance and planarity. The N lone pair delocalizes into the carbonyl, giving the CN\ce{C-N} bond partial double-bond character. Consequences: restricted C–N rotation, a planar amide bond, and lowered N basicity. This is why the peptide backbone is conformationally restricted — a direct protein-structure connection.

RC(=O)NHX2RC(OX)=NHX2X+\ce{R-C(=O)-NH2 <-> R-C(-O^-)=NH2^+}

Quick check: Why does acetamide (CHX3CONHX2\ce{CH3CONH2}) have a higher boiling point than acetic acid (CHX3COOH\ce{CH3COOH}) of nearly equal MW?

Answer: Acetamide has N–H donors plus a carbonyl acceptor, and its resonance-locked planar geometry enables very efficient intermolecular H-bonding. (Both are high boilers; the takeaway is that amides boil high because of N–H donation + carbonyl acceptance.)


Relative Reactivity of Acid Derivatives

Why Reactivity Differs

Must know

One of the most MCAT-tested ideas here. All derivatives react by nucleophilic acyl substitution but at very different rates, set by two factors: leaving-group ability and how much the heteroatom donates electron density into the carbonyl (lowering electrophilicity).

Reactivity order:

Acid chloride>Anhydride>Thioester>Ester>AmideCarboxylate\text{Acid chloride} > \text{Anhydride} > \text{Thioester} > \text{Ester} > \text{Amide} \gg \text{Carboxylate}

The more electrophilic the carbonyl carbon and the better the leaving group, the faster the reaction.

Electronic Effects

Know the logic

Leaving-group ability mirrors basicity in reverse — weaker base = better leaving group:

  • ClX\ce{Cl^-} very weak base → excellent LG → acid chlorides extremely reactive
  • carboxylate, then alkoxide → good/moderate LGs → anhydrides, then esters intermediate
  • amine = strong base → poor LG → amides least reactive

Also, nitrogen donates its lone pair into the carbonyl more strongly than oxygen (less electronegative, looser lone pair), making the amide carbonyl less electrophilic. Thioesters beat oxygen esters because sulfur's 3p overlaps poorly with the carbonyl 2p, so CS\ce{C-S} donation is weak and the carbonyl stays electrophilic — why acetyl-CoA is a high-energy acyl donor.

Steric effects: bulk near the carbonyl slows nucleophilic attack (more substituted = slower). Tested qualitatively.

Strain: β-Lactams

Must know

A β-lactam is a four-membered cyclic amide. Amides are normally least reactive, but β-lactams are a dramatic exception: severe ring strain (forced ~90° angles) is relieved on ring-opening, providing a strong driving force for nucleophilic attack.

This is how penicillin works: the strained ring acylates the active-site serine of bacterial transpeptidase (needed for cell-wall synthesis), inactivating it. β-lactamase-producing bacteria hydrolyze the ring first and are resistant.

Quick check: Which is more reactive toward hydrolysis — a simple primary amide (CHX3CONHX2\ce{CH3CONH2}) or penicillin G (a β-lactam)?

Answer: The β-lactam, by far. Both are amides, but the strained four-membered ring opens to relieve strain, making it much more electrophilic and kinetically accessible to attack.


General Principles: Nucleophilic Acyl Substitution

The Mechanism

Must know

Every reaction of an acid derivative with a nucleophile follows the same two steps:

1 — Addition: the nucleophile attacks the carbonyl carbon, breaking the π\pi bond to form a tetrahedral intermediate (the carbonyl O takes a negative charge).
2 — Elimination: the intermediate collapses, reforming the π\pi bond and expelling the leaving group.

NuX+RC(=O)LG[RC(Nu)(OX)(LG)]RC(=O)Nu+LGX\ce{Nu^- + R-C(=O)-LG -> [R-C(Nu)(O^-)(LG)] -> R-C(=O)-Nu + LG^-}

Key points: the tetrahedral species is a real intermediate (energy well), not just a transition state; the net result is substitution at an sp² carbon (unlike SN2S_N2 at sp³). Less reactive derivatives need stronger nucleophiles, heat, or acid/base catalysis.

Direction of Reactivity: Downhill Substitutions

Must know

You can convert a more reactive derivative into a less reactive one easily, not the reverse under normal conditions.

Acid chlorideROHEsterNHX3Amide\text{Acid chloride} \xrightarrow{\ce{ROH}} \text{Ester} \xrightarrow{\ce{NH3}} \text{Amide}

Acid chloride + alcohol → ester; ester + amine → amide. But an amide will not convert to an ester just by adding alcohol — that's "uphill."

Quick check: To make methyl benzoate from methanol, do you start from (a) benzoyl chloride or (b) benzamide?

Answer: (a). Acid chlorides react readily with alcohols (downhill); starting from an amide would require going uphill, which doesn't proceed under normal conditions.


Important Reactions

Hydrolysis of Esters

Must know

Acid-catalyzed hydrolysis is reversible (every step, including the proton transfers, is reversible) — drive it with excess water.

Base-promoted hydrolysis (saponification) is irreversible: hydroxide attacks, and the carboxylic acid product is immediately deprotonated to the resonance-stabilized carboxylate (a terrible electrophile), which pulls the reaction to completion.

RCOORX+NaOHRCOONa+RXOH\ce{RCOOR' + NaOH -> RCOONa + R'OH}

Saponification = "soap-making": base hydrolysis of triglycerides gives glycerol + fatty-acid salts (soaps) — a high-yield biological hook.

Stoichiometry note: saponification is 1:1 ester:NaOH, so moles of base = mass/MW of the ester. (E.g. 1.00 g ethyl acetate, MW 88.11 → ~0.0114 mol NaOH.)

Transesterification

Must know

Transesterification swaps the alkoxy group of an ester for another alcohol; acid- or base-catalyzed. Mechanism is identical to ester hydrolysis but the nucleophile is an alcohol instead of water.

RCOORX+RXOHHX+  or  baseRCOORX+RXOH\ce{RCOOR' + R''OH <=>[H+ \text{ or } base] RCOOR'' + R'OH}

It is an equilibrium driven by Le Chatelier (excess alcohol, or removing a volatile product). Biological/industrial relevance: triglyceride/phospholipid remodeling (lipases) and biodiesel (oil + methanol → methyl esters + glycerol).

Quick check: Acid-catalyzed transesterification of methyl propanoate (CHX3CHX2COOCHX3\ce{CH3CH2COOCH3}) with ethanol gives what?

Answer: Ethyl propanoate (CHX3CHX2COOCX2HX5\ce{CH3CH2COOC2H5}) + methanol. The ethyl group replaces the methyl on the ester oxygen.

Reduction of Acid Derivatives

Must know

LiAlHX4\ce{LiAlH4} — the N-vs-O distinction is high-yield:

  • Ester → primary alcohol (ORX\ce{-OR'} leaves): RCOORX2 HX3OX+1 LiAlHX4RCHX2OH+RXOH\ce{RCOOR' ->[1.~LiAlH4][2.~H3O+] RCH2OH + R'OH}
  • Amide → amine (C–N retained; only the carbonyl O is removed): RCONRX22 HX3OX+1 LiAlHX4RCHX2NRX2\ce{RCONR'2 ->[1.~LiAlH4][2.~H3O+] RCH2NR'2}

So ester → alcohol, amide → amine. (NaBHX4\ce{NaBH4} is too mild for either.)

Esters with Grignard Reagents

Know the logic

A Grignard (RXMgX\ce{R''MgX}) adds twice to an ester (the ketone intermediate is more reactive than the ester), giving a tertiary alcohol with two identical R'' groups:

RCOORX+2RXMgXRC(RX)X2OH (after workup)\ce{RCOOR' + 2 R''MgX -> R-C(R'')2-OH} \ (\text{after workup})

Hydrolysis of Amides

Must know

Requires forcing conditions (prolonged heat with concentrated acid or base) because amides are the least reactive derivative.

RCONHX2+HX2O+HX+ (cat)ΔRCOOH+NHX4X+\ce{RCONH2 + H2O + H+ (cat.) ->[\Delta] RCOOH + NH4+}
RCONHX2+NaOHΔRCOONa+NHX3\ce{RCONH2 + NaOH ->[\Delta] RCOONa + NH3}

Under acid the nitrogen leaves as NHX4X+\ce{NH4+} (product is the acid); under base it leaves as NHX3\ce{NH3} (product is the carboxylate).

Passage-level

Biological hook: proteins are polyamides; peptide-bond hydrolysis (proteases, or 6M HCl) is amide-hydrolysis chemistry. Serine proteases route it through an acyl-enzyme ester intermediate — turning slow amide hydrolysis into faster ester hydrolysis.

Quick check: Why is base-promoted amide hydrolysis irreversible?

Answer: As in saponification, the carboxylic acid is immediately deprotonated to the resonance-stabilized carboxylate (terrible electrophile). That final proton transfer is irreversible under base, driving the reaction to completion.


Anhydride Reactions

Must know

Anhydrides are more reactive than esters, less than acid chlorides. They react with:

  • Water → two carboxylic acids
  • Alcohols → one ester + one carboxylic acid
  • Amines → one amide + one carboxylic acid

(CHX3CO)X2O+CX2HX5OHCHX3COOCX2HX5+CHX3COOH\ce{(CH3CO)2O + C2H5OH -> CH3COOC2H5 + CH3COOH}
(CHX3CO)X2O+NHX3CHX3CONHX2+CHX3COOH\ce{(CH3CO)2O + NH3 -> CH3CONH2 + CH3COOH}

Phosphoanhydrides — The Biological Anhydride

Passage-level

A phosphoanhydride is the anhydride linkage between two phosphates. The terminal P–O–P bonds of ATP are phosphoanhydrides; their hydrolysis is strongly exergonic (charge repulsion + resonance stabilization of released PXi\ce{P_i}), the basis of ATP as energy currency — the same logic that makes carboxylic anhydrides reactive condensation products.

Optional

Aspirin: salicylic acid + acetic anhydride acetylates an –OH (forms an ester); aspirin then irreversibly acetylates the active-site serine of COX.

Quick check: Acetic anhydride + a primary amine RNHX2\ce{RNH2} gives which two products?

Answer: An amide (CHX3CONHR\ce{CH3CONHR}) and acetic acid (CHX3COOH\ce{CH3COOH}). The amine attacks the carbonyl; the carboxylate leaving group picks up a proton.


Common Confusions & Tricks

1. Transesterification direction. It's an equilibrium and can be pushed either way — excess alcohol or product removal (Le Chatelier). Don't assume it only goes "downhill."

2. Amide N vs. amine N. Amide nitrogen is a poor nucleophile and essentially non-basic (lone pair delocalized into the carbonyl); amine nitrogen is nucleophilic and basic. N next to a carbonyl = amide N — don't treat it as a normal amine.

3. Acid vs. base hydrolysis products. Acid: amine leaves as NHX4X+\ce{NH4+}, you get the carboxylic acid. Base: amine leaves as NHX3\ce{NH3}, you get the carboxylate salt.

4. β-Lactam reactivity. Amides are "least reactive," but a four-membered cyclic amide reacts fast — 100% due to ring strain relieved on opening. Four-membered cyclic amide ⇒ flag highly reactive.

5. Tetrahedral intermediate vs. transition state. The tetrahedral species is a true intermediate (energy well), unlike the SN2S_N2 pentacoordinate transition state (energy maximum).

6. Saponification irreversible; acid ester hydrolysis reversible. Irreversibility comes from the final deprotonation to carboxylate, not just nucleophile strength. Under acid, all proton transfers (and thus all steps) are reversible.

7. "Thioester = high energy." Acetyl-CoA is a thioester, sitting between anhydrides and esters in reactivity. Weak CS\ce{C-S} resonance overlap leaves the carbonyl electrophilic, making it a great acyl donor in biosynthesis.

8. Which group is "alkyl" in an ester name. The alkyl in "ethyl acetate" comes from the alcohol (OCX2HX5\ce{-OC2H5}); the carbonyl fragment gives "-anoate." The alkyl hangs off the ester oxygen.


Key Equations

Equation / RelationshipWhen to Use
Nucleophilic acyl substitution: NuX+RCOLGRCONu+LGX\ce{Nu^- + R-CO-LG -> R-CO-Nu + LG^-}Applies to all acid-derivative reactions
Saponification (irreversible): RCOORX+NaOHRCOONa+RXOH\ce{RCOOR' + NaOH -> RCOONa + R'OH}1:1 ester:NaOH; product is carboxylate; stoichiometry problems
Acid ester hydrolysis (reversible): RCOORX+HX2OHX+RCOOH+RXOH\ce{RCOOR' + H2O <=>[H+] RCOOH + R'OH}Reversible; drive with excess water; HX+\ce{H+} is catalyst
Transesterification: RCOORX+RXOHRCOORX+RXOH\ce{RCOOR' + R''OH <=> RCOOR'' + R'OH}Equilibrium; driven by excess alcohol or product removal
Amide hydrolysis (acidic): RCONHX2+HX2O+HX+RCOOH+NHX4X+\ce{RCONH2 + H2O + H+ -> RCOOH + NH4+}Heat + conc. acid; N leaves as ammonium
Amide hydrolysis (basic): RCONHX2+NaOHRCOONa+NHX3\ce{RCONH2 + NaOH -> RCOONa + NH3}Heat + conc. base; N leaves as free amine
Anhydride + alcohol: (RCO)X2O+RXOHRCOORX+RCOOH\ce{(RCO)2O + R'OH -> RCOOR' + RCOOH}One ester + one carboxylic acid
Anhydride + amine: (RCO)X2O+RXNHX2RCONHRX+RCOOH\ce{(RCO)2O + R'NH2 -> RCONHR' + RCOOH}One amide + one carboxylic acid
Reactivity order: acid chloride >> anhydride >> thioester >> ester >> amidePredict feasibility/direction of acyl transfer

Practice questions

Discrete practice questions written for this guide. Try them with full answers and explanations — sign in to save your progress.

Question 1 of 100 correct
discreteChem/Phys

Which functional group is a carboxylic acid derivative in which the carbonyl carbon is bonded to a nitrogen atom?